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CREATE TABLE a(b, c); SELECT c FROM a GROUP BY c HAVING(SELECT(sum(b) OVER(ORDER BY b), sum(b) OVER(PARTITION BY min(DISTINCT c), c ORDER BY b)));

Statistics for CREATE TABLE a(b, c); SELECT c FROM a GROUP BY c HAVING(SELECT(sum(b) OVER(ORDER BY b), sum(b) OVER(PARTITION BY min(DISTINCT c), c ORDER BY b)));:

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